If $\alpha = 0.98$ and the current through the emitter $i_e = 20 \, mA$,the value of $\beta$ is

In a transistor,in common emitter configuration,the ratio of power gain to voltage gain is

Consider an amplifier circuit wherein a transistor is used in common emitter mode. The change in collector current and base current respectively are $4 mA$ and $20 \mu A$ when a signal of $40 mV$ is added to the base-emitter voltage. If the load resistance is $10 k\Omega$,then the power gain in the circuit is:

The collector current in a common base amplifier using $n-p-n$ transistor is $24\; mA$. If $80\%$ of the electrons released by the emitter are accepted by the collector,then the base current is numerically

$A$ $n-p-n$ transistor is connected in common-emitter configuration in which the collector supply is $8\, V$ and the voltage drop across the load resistance of $800\,\Omega$ connected in the collector circuit is $0.8\, V$. If the current amplification factor $\alpha$ is $25/26$,the collector-emitter voltage $V_{CE}$ and the base current $I_B$ will be:

For a transistor,the current ratio $\alpha_{dc} = \frac{69}{70}$,the current gain $\beta_{dc}$ is